Math, asked by sandeepanjani26, 11 months ago

if the number obtained by interchanging the digits of a two digit number is 18 more than the original number and the sum of the digits is 8 then what is the original number

Answers

Answered by spiderman2019

Answer:

Step-by-step explanation:

Let x and y be the digits of the number. The number is 10x+y

sum of the digits is 8 => x + y = 8. -------------> Equation 1

number obtained by interchanging the digits of a two digit number is 18 more than the original number

=> (10y+x) - (10x+y) = 18

=> 9y - 9x = 2

=> y - x = 2 --------------------> Equation 2

Add equation 1 and Equation 2.

x + y = 8

-x+y = 2

--------------

2y = 10 => y = 5.

----------------------------

Substitute in y = 5 in equation 1

x + y = 8 => x + 5 = 8 => x =3.

Thus the original number is 35

Answered by MRsteveAustiN

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if the number obtained by interchanging the digits of a two digit number is 18 more than the original number and the sum of the digits is 8 then what is the original number ​

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if the number obtained by interchanging the digits of a two digit number is 18 more than the original number and the sum of the digits is 8 then what is the original number