Question

if the number obtained by reversing the digit of a two digit number is 9 less than the original number and the sum of digit of the number is 15 . find the original number

Answer 1

let unit digit be x tenth digit be y
no.=10y+x
reverse no.=10x+y
x+y=15(given)
a/q
10x+y+9=10y+x
10x-x+y-10y=-9
9x-9y=-9
9(x-y)=-9
x-y=-1
x+y=15
then2x=14
x=7
theny=7+1(fromx-y=1)
y=8 then no.=10×8+7=87
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