Question

If the number of a fraction is increased by 20% and the denominator is decreased by 5%, the value of the new fraction become 5/2 .Find the original fraction.​

Answer 1

Answer:

The original fraction is 95/12

Step-by-step explanation:

Given:
Numerator increased by 20%
Denominator decreased by 5%

Value of the new fraction formed = 5/2

Let, the original friction be p/q
now, 20% of p = 20p/100 = p/5

5% of q = 5q/100 = q/20

∵ Numerator is increased

∴ p + p/5 = 6p/5
∵ Denominator is decreased
∴ q - q/20 = 19q/20
Now,
(6p/5)/(19q/5) = 5/2

⇒(6p/5) × (5/19q) = 5/2

⇒ 6p/19q = 5/2

⇒ p/q = (5×19)/(6×2)

⇒ p/q = 95/12

Answer 2

Hope my answer helps you friend :)

Solution:-

Let the fraction = x/y

According to the question,

x × 120 / y × 95 = 5 / 2

x / y= 5 × 95 / 2 × 120 = 95 / 48 (Answer)

Thank you!