Question

If the number of bivalent are 8 in metaphase 1 what shall be the number of chromosomes in daughter cells after meiosis 1 and meiosis 2 respectively

Answer 1

Answer:

So, if the bivalents are \[8\] in number at metaphase I, the number of chromosomes in daughter cells after meiosis I and meiosis II will also be \[8\] and \[8\] respectively. A single bivalent has \[2\] chromosomes. So, \[8\]bivalents will have \[16\] chromosomes