Question

If the number of divisions on the circular scale is 100 and number of full rotations given to screw is 8 and distance moved by the screw is 4 mm, then what will be least count of the screw gauge ?

Answer 1

Explanation:

Hey ❗❗

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↪Here number of divisions on circular scale = 100

↪Number of complete rotation = 4

↪Distance moved = 2 mm

↪Pitch = Distance moved / Number of complete rotations

↪2mm / 4

↪0.5 mm

↪Least count = Pitch / Number of divisions on circular scale .

↪0 . 5mm / 100

↪0.005mm

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Answer 2

Answer:

above is best .....answer .....least count of the screw gauge ?