Question

If the number of dots on the upward faces of two standard six sided dice give the score for that throw what is the probability of making a score of 7 in one throw of a pair of fair dice

Answer 1

Step-by-step explanation:

When 2 dice are rolled total possible outcomes are 36. They are :-

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Total favourable outcomes to get a sum of 7 when 2 dice are rolled simultaneously = 6

{i.e.,(1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Probability = favourable outcomes /total outcomes

P = 6/36

P = 1/6.

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