Question

if the number of electron of 5×10¹⁰ flows to obtain how much electrical charge​

Answer 1

Given :-

No. of electrons = n = 5 × 10¹⁰

Charge on electron = e = 1.6 × 10-¹⁹ C

As we know that,

Charge is the integral multiple of electronic charges.

Q = ±ne

Q = 5 × 10¹⁰ × 1.6 × 10-¹⁹

$\bf{Q\:=\:8\times{10}^{-9}\:C}$