Question

If the number of loops in a solenoid per unit length is
10/m and the current passing through it is 2A.

then find the magnetic field at the centre of the solenoid.​

Answer 1

${ \textsf{ \textbf{ \orange{ \underline{answer}}}}}$

Given that,

A solenoid has 1000 turns per meter length.

Current = 5 A

We need to calculate the magnetic field inside the solenoid

Using formula of magnetic field

$B=\mu_{0}$

$Where, n =\dfrac{N}{l}$

= turns per meter length

• I = current

• B = magnetic field

Put the value into the formula

$B=4\pi\times10^{-7}\times1000\times5B=$

$B=0.00628\ TB=$

B=6.28\ mTB=6.28 mT

Hence, The magnetic field inside the solenoid is 6.28 mT.

Learn more :

Topic : magnetic field

https://brainly.in/question/13427081

Answer 2

$\huge{\underline{\underline{\boxed{\sf{\purple{Answer࿐}}}}}}$

The magnetic field inside the solenoid is 6.28 mT.