If the number of numbers between 100 and 1000 that are divisible by 11 is x,
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here, t1=121 d=11, tn=990.
we know that,
tn=a+(n-1)d
990=121+(n-1)11
990=121+11n-11
990=110+11n
990-110=11n
880=11n
880/11=n
80=n. : there are 80 number are divisible by 11 in 100to1000.
pratiksk7:
is it right
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