Question

If the number of pages he read on second , third and fourth day is half the number of pages he read on previous day. Find the number of pages he read on the first day.​

Answer 1

Answer:

First day he read 160 pages.

Step-by-step explanation:

Given:

If the number of pages he read on second , third and fourth day is half the number of pages he read on previous day .

To find:

the number of pages he read on the first day ?

Solution:

According to the given question

let he read on fourth day = x pages

Third day = 2x pages

second day = 4x pages

First day = 8x pages

Given total number of pages = 300

8x + 4x + 2x + x = 300

15 x = 300

X = 300 / 15

X = 20

so , fourth day = 20 pages

Third day 2x = 2(20) = 40 pages

second day 4x = 4(20) = 80 pages

First day = 8x = 8(20) = 160 pages.

$\bold {First \: day \: he \: read \: 160 \: pages.}$

Answer 2

Answer:

200

Step-by-step explanation:

Let the value of pages read on first day be x.

Then, x+x/2=300

x/1+x/2 ( lcm= 2, so 1*2 and x*2)

2x/2+x/2=300

3x/2=300

3x=300*2
x=600/3
x=200