if the number of sides of a polygon is 11 , then find the sum of its angles
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sum of internal angles is (n-2)*180
(11-2)*180
9*180
1620
hope this helps u
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(11-2)*180
9*180
1620
hope this helps u
please mark brainliest
Answered by
1
The sum of all the interior angles of a polygon with sides n is equal to
( 2n - 4) x 90°
Therefore,
= 2n - 4 x 90°
= 2 x 11 -4 x 90°
= 22 - 4 x 90°
= 18 x 90°
= 1620°
rajaluxmy1967:
why don't you mark the brainliest also
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