Question

if the number of surfaces of a cuboid is x number of edges is y and number of vertices is z then find yz÷x?​

Answer 1

Answer:

12

Step-by-step explanation:

In cuboid –number of surfaces = 6 = x

number of edges = 12 = y

number of vertices = 8 = z

number of diagonal = surface diagonal + body diagonal = 6 + 4 = 10 = p

Thus, x-y + z + p = 6-12 + 8 + 10 = 12.

Answer 2

Answer:

As it is given ,

If the number of surfaces of a cuboid is x number of edges is y and the number of vertices is z , then find yz ÷ x = ??

Ans --> In cuboid the number of surfaces

= 6 => x ( Given )

The number of edges = 12 => y ( Given )

The number of vertices = 8 => z ( Given )

As we know that ,

Number of diagonal = surface diagonal +

body diagonal.

Now , putting the values of x, y, and z .

=> 6 + 4 = 10 => P .

Therefore, x - y + z + p

=> 6 - 12 + 8 + 10

=> 12 ( Final answer )

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