if the number of surfaces of a cuboid is x number of edges is y and number of vertices is z then find yz÷x?
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Answered by
1
Answer:
12
Step-by-step explanation:
In cuboid –number of surfaces = 6 = x
number of edges = 12 = y
number of vertices = 8 = z
number of diagonal = surface diagonal + body diagonal = 6 + 4 = 10 = p
Thus, x-y + z + p = 6-12 + 8 + 10 = 12.
Answered by
3
Answer:
As it is given ,
If the number of surfaces of a cuboid is x number of edges is y and the number of vertices is z , then find yz ÷ x = ??
Ans --> In cuboid the number of surfaces
= 6 => x ( Given )
The number of edges = 12 => y ( Given )
The number of vertices = 8 => z ( Given )
As we know that ,
Number of diagonal = surface diagonal +
body diagonal.
Now , putting the values of x, y, and z .
=> 6 + 4 = 10 => P .
Therefore, x - y + z + p
=> 6 - 12 + 8 + 10
=> 12 ( Final answer )
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