Question

If the number of two digits is k times the sum of its digits

Answer 1

Let the two digit number be 10x+y. Hence, the number obtained on interchanging the digits is 10y+x. Also, sum of digits is x+y.

So, we get,

10x+y=K(x+y)   -(1)

10y+x=N(x+y)   -(2)

Adding (1) and (2) we get,

11(x+y)=(N+K)(x+y)

Therefore, N+K=11

N=11-K.

Answer 2

Answer:

Let the two digit number be 10x+y. Hence, the number obtained on interchanging the digits is 10y+x. Also, sum of digits is x+y.

So, we get,

10x+y=K(x+y)   -(1)

10y+x=N(x+y)   -(2)

Adding (1) and (2) we get,

11(x+y)=(N+K)(x+y)

Therefore, N+K=11

N=11-K.

Step-by-step explanation: