if the number p^n
and ever to end with digit 0 then what are the possible value of p
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If p^n should be in the form of (2^n ×5^n)
then the product will end with digit 0.
for example:-
if 6^n is given ...
then the factors should be in the form of (2^n × 5^n)
then it is will end with the digit 0
but the factors of 6 =2×3
it has 2 in it but not 5
therefore, it will not end with the number 0
then the product will end with digit 0.
for example:-
if 6^n is given ...
then the factors should be in the form of (2^n × 5^n)
then it is will end with the digit 0
but the factors of 6 =2×3
it has 2 in it but not 5
therefore, it will not end with the number 0
punishbhao:
ohh grt answer dear
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1
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Step-by-step explanation:here is your answer
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