If the number pis 7 more than
the number g and the sums of
the squares of p and q is 85.
find the difference of cube of
p and a
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Answer:-
Given:-
A number p is 7 more than q.
→ p = q + 7
→ p - q = 7 -- equation (1)
And,
Sum of their squares = 85
→ p² + q² = 85 -- equation (2)
We know that,
(a - b)² = a² + b² - 2ab
Hence,
→ (p - q)² = (p² + q²) - 2pq
Putting the values from equations (1) & (2) we get,
→ (7)² = (85) - 2pq
→ 49 - 85 = - 2 pq
→ - 36/ - 2 = pq
→ pq = 18 -- equation (3)
We know,
a³ - b³ = (a - b) * (a² + b² + ab)
→ p³ - q³ = (p - q) * (p² + q² + pq)
Putting the values from equations (1) , (2) and (3) we get,
→ p³ - q³ = (7) * ( 85 + 18)
→ p³ - q³ = (7) * (103)
→ p³ - q³ = 721
Hence, the difference of cubes of p and q is 721.
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