Question

if the number x is 3 less than the number y and the sum of the squares of x and y is 29 ,find the product of x and y

Answer 1

Hii friend,

Numbers are X and Y.

X = Y-3

According to question,

(Y-3)² + (Y)² = 29

Y²+(3)² - 2 × Y× 3 = 29

Answer 2

given
$y - x = 3$
$so \\ (y - x) {}^{2} = (3) {}^{2} \\ = > y {}^{2} + x {}^{2} - 2xy = 9$
given
$y {}^{2} + x {}^{2} = 29$
so
$y {}^{2} + x {}^{2} - 2xy = 9 \\ = = > 29 - 2xy = 9 \\ 2xy = 9 - 29 \\ 2xy = - 20 \\ xy = - 10$
XY= -10
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