If the number x is 3 less than the number y and the sum of the squares of x and y
29, find the product of x and y.
um and the product of two numbers are 8 and 15 respectively, find the sum
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Answer:
Question 1.
x-3=y
x^2+y^2=29
=>x^2+(x-3)^2=29
=>x^2+x^2-6x+9=29
=>2x^2-6x-20=0
=>x=5 or -2=>y=2 or -5
Now,the product of x and y=10 .
Question 2.
Let,the two numbers are x and y.
Given, x+y=8
xy=15
(x-y)^2=(x+y)^2-4xy=64-60=4=>x-y=2
Now, solving (x+y) and (x-y), we get
x=5 and y=3 .
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