Question

if the numbers 2K-3,K+1,2K+3 in AP ,find the numbers​

Answer 1

Answer:

if these are in AP

then

$d = k + 1 - (2k - 3) - - - (1)$

and

$d = 2k + 3 - (k + 1) - - - (2)$

by 1 and 2

$k + 1 - 2k + 3 = 2k + 3 - k - 1$

$- k + 4 = k + 2$

$2k = 2$

$k = \frac{2}{2} = 1$

•°•k=1

2k-3=2 (1)-3=2-3=-1

k+1=1+1=2

2k+3=2 (1)+3=2+3=5

•°•AP is -1,2,5-----

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Answer 2

Answer - AP is -1, 2, 5

Hope it will help! Thank You! :)