Question

If the
numbers (2n-1), (3n+2) and (60-1)
are in AP find the value of n and the number.​

Answer 1

Answer:

3

Step-by-step explanation:

$(3n + 2) - (2n - 1) = (6n - 1) - (3n - 2)$

$3n + 2 - 2n + 1 = 6n - 1 - 3n - 2$

$n + 3 = 3n - 3$

$6 = 2n$

$n = 3$

HOPE THIS HELPS YOU

PLEASE FOLLOW AND MARK AS BRAINLIEST

Answer 2

Step-by-step explanation:

common difference has to be equal

(3n+2)-(2n-1)= (60-1n)-(3n+2)

=3n+2-2n+1=60-n-3n-2

=n+3=58-4n

=n+4n=58-3

=5n=55

=n=55/5=11