If the numbers 2n-1, 3n+2 and 6n-1 are in AP ,find the value of n?
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2(3n+2)=(2n-1)+(6n-1)
6n+4=8n-2
4+2=8n-6n
6=2n
n=6/2
n=3
romysharma:
may be
you can ask
1st question is -- solve the following pair of linear equations algebraically - 37X+43y= 123 ; 43X+37y=117
Please give me answer
ist equation ko 43 se multiply krdo second ko 37 se
then dono ko minus krdo you will get value of x after that y
I can't understand your language use English please
Where are you from
firstly you multiply the first equation with 43 and the second equation with 37
then subtract both the equation and get x after that y
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