Math, asked by Mguamaruthamuthu, 11 months ago

If the numbers 2n-1, 3n+2 and 6n-1 are in AP ,find the value of n?

Answers

Answered by romysharma

2(3n+2)=(2n-1)+(6n-1)

6n+4=8n-2

4+2=8n-6n

6=2n

n=6/2

n=3

romysharma: may be

romysharma: you can ask

Mguamaruthamuthu: 1st question is -- solve the following pair of linear equations algebraically - 37X+43y= 123 ; 43X+37y=117

Mguamaruthamuthu: Please give me answer

romysharma: ist equation ko 43 se multiply krdo second ko 37 se

romysharma: then dono ko minus krdo you will get value of x after that y

Mguamaruthamuthu: I can't understand your language use English please

Mguamaruthamuthu: Where are you from

romysharma: firstly you multiply the first equation with 43 and the second equation with 37

romysharma: then subtract both the equation and get x after that y

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