Question

if the numbers 2n-1,n-1,and 3n-10 are in A.P.,find n

Answer 1

Step-by-step explanation:

if 2n-1,n-1 and 3n-10 are in AP, then:

2(n-1)=2n-1+3n-10

2n-2=5n-11

5n-2n-11+2=0

3n-9=0

3n=9

n=3

Answer 2

Answer:

3

Step-by-step explanation:

2n-1, n-1, 3n-10 are in AP

So, (n-1)-(2n-1) = (3n-10)-(n-1)

     -n = 2n-9

     n = 3