Math, asked by chandans0183cs, 8 months ago

If the numbers a, b, c, d, e
form an A.P., then the value
of a - 4b +6C - 4d + e is​

Answers

Answered by st6531779
5

Answer:

0

Step-by-step explanation:

ANSWER

a,b,c,d,e are in A.P

∴b=a+D

c=a+2D

d=a+3D

e=a+4D

Here D is the common difference substitute the values of b,c,d and e in the given expression.

a−4b+6c−4d+e

=a−4(a+D)+6(a+2D)−4(a+3D)+a+4D

=a−4a−4D+6a+12D−4a−12D+a+4D

=8a−8a

=0

Answered by sathyamargerate0410
1

Step-by-step explanation:

If a, b, c, d, e are in A. P

a=a b=a+d c=a+2d d=a+3d e=a+4d

a-4b+6c-4d+e

a-4(a+d)+6(a+2d)-4(a+3d)+a+4d

a-4a-4d+6a+12d-4a-12d+a+4d

(1-4+6-4+1)a+(-4+12-12+4)d

0a+0d

0

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