Question

If the numbers from 6 to 79 which are exactly divisible by 3 are arranged in the descending order, then which would come at the seventh place from the bottom?​

Answer 1

Answer:

The seventh number from the bottom position will be: 24

Step-by-step explanation:

As per the data given in the question,

We have to determine, which number would come at the seventh place from the bottom when the numbers from 6 to 79 which are exactly divisible by 3 are arranged in the descending order

As here,

The first number will be 6 and the subsequent number can be determined by adding 3 to the previous numbers.

So, the number will be:

6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78

As all numbers are supposed to be arranged in descending order.

As we know,

In descending order, we put the largest number first and the lesser number comes later.

So, when we arrange all such numbers in descending order, 78 will come on top and 6 will come on the bottom position.

So, the number from the bottom position will be like 6, 9, 12, 15, 18, 21, 24, 27......

So, the seventh number from the bottom position will be: 24

For such more questions: https://brainly.in/question/42075710

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