Question

If the numbers n-2, 4n - 1 and 5n + 2 are in AP, find the value of n.​

Answer 1

Answer:

Step-by-step explanation:

4n-1-(n-2)=5n+2-(4n-1)

4n-1-n+2=5n+2-4n+1

4n+4n-5n-n=2+1+1-2

2n=2

n=1

Answer 2

Topic:- Arithmetic Sequence or Progression

Let to T1=n-2

Let to be T2=4n-1

Let to be THE=5n+2

Now..

T2-T1=T3-T2

4n-1-(n-2)=5n+2-(4n-1)

4n-1-n+2=5n+2-4n+1

4n-n+2-1=5n-4n+2+1

3n+1=n+3

3n-n=3-1

2n=2

n=2/2

n=1