Question

If the numbers n-2 ,4n -1 and 5n+2 are in AP then the value of n is____ *


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Answer 1

Answer:

here we can find it by common difference,that is, d

d=a2 -a1

d= (4n-1)-(n-2)

d= 4n-1 -n +2

d= 3n +1

now, d= a3-a2

3n+1= 5n+2 -4n+1

3n+1=n+3

3n-n=3-1

2n=2

n=2/2

n=1...

hope it helps.....please mark it as brainliest