Question

If the numbers p-1,p+3 , 3p-1 are in A.P., find the value of p.

Answer 1

hello users .....

we have given that
p-1,p+3 , 3p-1 are in A.P

we have to find p= ?

solution :-
we know that :
if a,b,c are in AP
then 2b = a + c

here
=> 2(p+3) = { (p-1) + ( 3p -1) }

=> 2p +6 = 4p -2

=> 2p = 8

=> p = 4 answer

⭐⭐ hope it helps ⭐⭐

Answer 2

The value of $p$ is $4$.

Solution with detailed explanation :

Given :

The numbers $(p-1)$, $(p+3)$ and $(3p-1)$ are in Arithmetic Progression

To find :

The value of $p$

Solution :

Since the numbers $(p-1)$, $(p+3)$ and $(3p-1)$ are in Arithmetic Progression, the respective common differences are equal

$\Rightarrow (p+3)-(p-1)=(3p-1)-(p+3)$

$\Rightarrow p+3-p+1=3p-1-p-3$

$\Rightarrow 4=2p-4$

$\Rightarrow 2p=8$

$\Rightarrow \boxed{p=4}$

Read more on Brainly.in

The smallest positive integer that appears in each of the arithmetic progression 5, 16, 27, 38, 49, ...; 7, 20, 33, 46, 59; ...

https://brainly.in/question/13420939