If the numbers x – 2, 4 x – 1 and 5x + 2 are in A P , THEN FIND THE VALUE OF X?
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ANSWERx-2, 4x-1 and 5x+2 are in AP. Therefore,
ANSWERx-2, 4x-1 and 5x+2 are in AP. Therefore,2(4x−1)=x−2+5x+2
ANSWERx-2, 4x-1 and 5x+2 are in AP. Therefore,2(4x−1)=x−2+5x+28x−6x=2
ANSWERx-2, 4x-1 and 5x+2 are in AP. Therefore,2(4x−1)=x−2+5x+28x−6x=22x=2
ANSWERx-2, 4x-1 and 5x+2 are in AP. Therefore,2(4x−1)=x−2+5x+28x−6x=22x=2x=1
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