If the numbers (x-2), (4x-1), (5x+2) are in A.P. find x.
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Question:
If the numbers (x-2), (4x-1), (5x+2) are in A.P. find x.
Given:
(x-2),(4x-1) and (5x+2) are in AP.
Solution:
First term(a) = x-2
Second term(a+d) = 4x-1
Third term(a+2d) = 5x+2
Since the three numbers are in AP, the common difference between these terms are the same.
ATQ,
4x-1-x+2 = 5x+2-4x+1
3x-1 = x+3
3x-x = 3+1
2x = 4
x = 2
Hope this helps. Please mark as brainliest.
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