If the numbers x + 3, 2x + 1 and x-7 are in AP. Find the value of x
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Answered by
3
a2-a1=a3-a2
2x+1-(x+3)=x-7-(x+3)
2x+1-x-3=x-7-x-3
x-2 = -10
x =-8
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Answered by
0
Step-by-step explanation:
let a be first no.and d be common difference
a=x+3
2x+1=a+d
2x+1=x+3+d
x=2+d. (i)
x-7=a+2d
x-7=x+3+2d
d=-5 put into i
x=2-5
x=-3
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