If the numerator and denominator of a certain fraction are increased by 2,the
fraction becomes 3/5. If numerator and denomenator are increased by 1,it becomes 1/2.find the fraction?
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HI !
Let the numerator be x and the denominator be y.
the fraction would be x/y
given ,
cross multiply ,
5(x+2) = 3(y+2)
5x + 10 = 3y + 6
5x - 3y = -4 ----> {1}
==========================================
also ,
cross multiply ,
2(x+1) = y + 1
2x + 2 = y + 1
2x - y = -1 ---> [2]
solving equations 1 and 2 by elimination method ,
2x - y = -1
5x - 3y = -4
2x - y = -1 = 3(2x - y = -1 )
= 6x - 3y =-3
6x - 3y =-3
- 5x - 3y = -4
==============
x = 1
2x - y = -1
2 - y = -1
y = 2 + 1 = 3
=================================
x = 1 , y = 3
the fraction is 1/3
Let the numerator be x and the denominator be y.
the fraction would be x/y
given ,
cross multiply ,
5(x+2) = 3(y+2)
5x + 10 = 3y + 6
5x - 3y = -4 ----> {1}
==========================================
also ,
cross multiply ,
2(x+1) = y + 1
2x + 2 = y + 1
2x - y = -1 ---> [2]
solving equations 1 and 2 by elimination method ,
2x - y = -1
5x - 3y = -4
2x - y = -1 = 3(2x - y = -1 )
= 6x - 3y =-3
6x - 3y =-3
- 5x - 3y = -4
==============
x = 1
2x - y = -1
2 - y = -1
y = 2 + 1 = 3
=================================
x = 1 , y = 3
the fraction is 1/3
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