If the numerator and denominator of a fraction are increased by 2 and 1 respectively it becomes 3/4, if the numerator and denominator are decreased by 2 and 1 respectively it becomes 1/2. find the fraction
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Answered by
121
Answer: 7/11
Step-by-step explanation:
Let the numerator be x and denominator be y.
(x + 2) ÷ (y + 1) = 3/4
Cross multiplication
4 (x + 2) = 3 (y + 1)
4x + 8 = 3y + 3
4x - 3y = -5 → ①
(x - 2) ÷ (y - 1) = 1/2
Cross multiplication
2 (x - 2) = y - 1
2x - 4 = y - 1
2x - y = 3. → ②
Multiply eqn ① by 1 and eqn ② by 2
Eqn ① by 1 - 4x - 3y = -5
Eqn ② by 2 - 4x -2y = 6
Subtract eqn ② from eqn ①
4x - 3y - 4x + 2y = -5 - 6
-y = -11
y = 11
Sub y = 11 in eqn ②
2x - 11 = 3
2x = 14
x = 7
Fraction = x/y = 7/ 11
harshdev017:
Thank you so much
Answered by
19
Answer:
fraction=x/y=7/11
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