Question

if the numerator is increased by 2 it becomes 1 by 2 and if the the denominator is decresed by 1 it becomes 1 by 3​

Answer 1

Step-by-step explanation:

Let the fraction be

y

x

As per the given statements,

y−4

x+2

=2

⇒x+2=2y−8

⇒x−2y=−10 --- (1)

Also,

y+2

x−1

=

3

1

⇒3x−3=y+2

⇒3x−y=5 --- (2)

Multiplying eqn (2) by 2 and subtracting eqn (1) from it, we get

2(3x−y)−(x−2y)=2(5)−(−10)

⇒5x=20

⇒x=4

Substituting this value of x in eqn (2), we get

3(4)−y=5

⇒y=12−5=7

∴x=4;y=7

So, x+y=4+7=11

Answer 2

Step-by-step explanation:

according to the condition

x/y is a fraction

x+2/y=1/2

2x+4=y

2x-y= -4

x/y-1=1/3

3x=y-1

3x-y= -1

substract 2 eq

2x-y= -4

- 3x-y= -1

-x=-3

x=3

y=10

fraction will be 3/10