Question

if the numerator of a a fraction is increased by 2 and it's denominator is decreased by 1,then it becomes2/3.
if the numerator is increased by 1 and denominator increased by 2,then it becomes 1/3
find the fraction

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Answer 1

Answer:

0 and 0 are your answer

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Answer 2

EXPLANATION.

GIVEN

Let the numerator be = x

Let the denominator be = y

CASE = 1.

If the numerator of a fraction is increased by

2 and it's denominator is decreased by 1

it becomes = 2/3

=> x + 2 / y - 1 = 2/3

=> 3 ( x + 2 ) = 2 ( y - 1 )

=> 3x + 6 = 2y - 2

=> 3x - 2y = -8 ......(1)

CASE = 2.

if the numerator is increased by 1 and

denominator increased by 2

it becomes = 1/3

=> x + 1 / y + 2 = 1/3

=> 3 ( x + 1 ) = 1 ( y + 2 )

=> 3x + 3 = y + 2

=> 3x - y = -1 .......(2)

From equation (1) and (2) we get,

=> 3x - 2y = -8 .....(1)

=> 3x - y = -1 ......(2)

multiply equation (1) by 1

multiply equation (2) by 2

we get,

=> 3x - 2y = -8

=> 6x - 2y = -2

we get,

=> -3x = -6

=> x = 2

put the value of x = 2 in equation (1)

we get,

=> 3(2) - 2y = -8

=> 6 - 2y = -8

=> -2y = -14

=> y = 7

Therefore,

original fraction =x/y = 2/7