If the numerator of a fraction is increased by 1/4 & its denominator is decreased by 1/3 then the fraction so obtained is 33/64. what is the original fraction?
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The numerator of the original fraction be "x"
the denominator of the original fraction be "y"
the numerator of the fraction has been increased by 1/4 then
x+1/4 of x
x+1/4*(symbol of multiplication)x
x+1/4*x
(4x+x)/4
5x/4
the denominator of the fraction has been decreased by 1/3 then
y-1/3*y
(3y-y)/3
2y/3
then
33/64 =(5x/4)/(2y/3)
22y= 80x
22/80=x/y
then
the fraction is 22/80
the denominator of the original fraction be "y"
the numerator of the fraction has been increased by 1/4 then
x+1/4 of x
x+1/4*(symbol of multiplication)x
x+1/4*x
(4x+x)/4
5x/4
the denominator of the fraction has been decreased by 1/3 then
y-1/3*y
(3y-y)/3
2y/3
then
33/64 =(5x/4)/(2y/3)
22y= 80x
22/80=x/y
then
the fraction is 22/80
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