Question

If the numerator of a fraction is increased by 10% and denominator is decreased be 10%,the resultantfraction is 5/7 times of its square.Find the fraction

Answer 1

Fraction will be $\frac{7}{45}$

Step-by-step explanation:

Let the fraction is $\frac{x}{y}$

Numerator is increased by 10% ,so it will become x+0.1x = 1.1x

And denominator is decreased by 10%, so it will become x-0.1x = 0.9x

Now according to question $\frac{0.1x}{0.9y}=\frac{5}{7}\frac{x^2}{y^2}$

$\frac{1}{9}=\frac{5x}{7y}$

$\frac{x}{y}=\frac{7}{45}$

So fraction will be $\frac{7}{45}$

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Answer 2

Answer:

77/45 is the correct answer