Question

If the numerator of a fraction is increased by 15% and its denominator is decreased by 8%,The Value of the fraction is 15/16. Find the original fraction

Answer 1

cheers and keep going...

Answer 2

Answer:

$\frac{3}{4}$.

Step-by-step explanation:

Let the numerator be x

Let the denominator be y

So, Fraction= $\frac{x}{y}$

Now we are given that the numerator of a fraction is increased by 15%

So, numerator = $x+15\% \times x$

                       = $x+\frac{15}{100} \times x$

                       = $1.15x$

Now we are given that its denominator is decreased by 8%

So, Denominator =  $y-8\% \times y$

                            = $y-\frac{8}{100} \times y$

                            = $0.92y$

So, The Value of the fraction is 15/16.

$\Rightarrow \frac{1.15x}{0.92y}=\frac{15}{16}$

$\Rightarrow \frac{x}{y}=\frac{0.92\times 15}{16 \times 1.15}$

$\Rightarrow \frac{x}{y}=\frac{3}{4}$

Hence the original fraction is $\frac{3}{4}$.