Question

if the numerator of a fraction is increased by 20% and its denominator Bidaai managed by 10% the value of the fraction is 16 by 21 the original fraction is​

Answer 1

Let the fraction be x/y.

Then from the given condition,

x+20percent of x /x-10percent of y = 16/ 21

x+x/5 / y-y/10 = 16/21

6x/5 / 9y/10 = 16/21

x/y=16/21 *9/10*5/6=4/7

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