Question

If the numerator of a fraction is increased by 25% and the denominator is increased by
10%, it becomes2/5 . Find the original fraction.​

Answer 1

Step-by-step explanation:

let numerator be p

and denominator be q

then the fraction becomes p/q

According to question,

If the numerator of fraction is increased

by 25% and the denominator

increased by 10% it becomes 2/5

thus,

(p + p × 25/100)/(q + q × 10/100) = 2/5

[100p + 25p]/100/[100q + 10q]/100 = 2/5

[125p/100]/[110q/100] = 2/5

125p/110q = 2/5

p/q = 2/5 × 110/125

p/q = 220/625

p/q = 44/125

Therefore the original fraction is

44/125.

Answer 2

Answer:

44/125

required fraction

= (2 - 20% of 2)/ (5 - 100/11 % of 5)

= (2 - 2/5) /(5 - 5/11)

= 8/5/50/11 = 8/5 × 11/50

= 88/ 250 = 44/125