If the numerator of a fraction is multiplied by 2 and the denominator is reduced by 5 the fraction becomes 6/5. And, if the denominator is doubled and the numerator is increased by 8, the fraction becomes 2/5. Find the fraction.
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Heya !!!
Let the numerator and denominator of fraction be X and Y.
Fraction = Numerator/Denominator = X/Y.
According to question,
X × 2 / Y - 5 = 6/5
2X/Y-5 = 6/5
5 × 2X = 6(Y-5)
10X = 6Y - 30
10X - 6Y = -30------------(1)
And,
X + 8/2Y = 2/5
5(X+8) = 2Y × 2
5X + 40 = 4Y
5X - 4Y = -40-----------(2)
From equation (1) we get,
10X - 6Y = -30
10X = -30 + 6Y
X = -30+6Y/10---------(3)
Putting the value of X in equation (2)
5X - 4Y = -40
5 × (-30+6Y/10) - 4Y = -40
-30+6Y/2 - 4Y = -40
-30 + 6Y - 8Y/2 = -40
-2Y - 30 = -40 × 2
-2Y - 30 = -80
-2Y = -80+ 30
-2Y = -50
Y = -50/-2 => 25
Putting the value of Y in equation (3)
X = -30 + 6Y/10 => -30 + 6 × 25/10
X = -30 + 150/10 => 120/10 =12
Therefore,
Numerator of fraction = X = 12
And,
Denominator of fraction = Y = 25
Fraction = Numerator/Denominator = 12/25
HOPE IT WILL HELP YOU...... :-)
Let the numerator and denominator of fraction be X and Y.
Fraction = Numerator/Denominator = X/Y.
According to question,
X × 2 / Y - 5 = 6/5
2X/Y-5 = 6/5
5 × 2X = 6(Y-5)
10X = 6Y - 30
10X - 6Y = -30------------(1)
And,
X + 8/2Y = 2/5
5(X+8) = 2Y × 2
5X + 40 = 4Y
5X - 4Y = -40-----------(2)
From equation (1) we get,
10X - 6Y = -30
10X = -30 + 6Y
X = -30+6Y/10---------(3)
Putting the value of X in equation (2)
5X - 4Y = -40
5 × (-30+6Y/10) - 4Y = -40
-30+6Y/2 - 4Y = -40
-30 + 6Y - 8Y/2 = -40
-2Y - 30 = -40 × 2
-2Y - 30 = -80
-2Y = -80+ 30
-2Y = -50
Y = -50/-2 => 25
Putting the value of Y in equation (3)
X = -30 + 6Y/10 => -30 + 6 × 25/10
X = -30 + 150/10 => 120/10 =12
Therefore,
Numerator of fraction = X = 12
And,
Denominator of fraction = Y = 25
Fraction = Numerator/Denominator = 12/25
HOPE IT WILL HELP YOU...... :-)
VijayaLaxmiMehra1:
its wrong answer:-(
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