Question

if the numerator of a franction is increased by 400% and the denominator is increased by 500% the resultant franction is 10/21,what was the original franction?

Answer 1

hey friend your answer is here

suppose x/y is a fraction then
(x+400/100)/(y+500/100) = 10/21
(x+4)/(y+5) = 10/21
x/y = (10-4)/(21-5)
x/y = 6/16

please make me a brainlist answer for the question

Answer 2

hey dear

[ Tex ] \ text maths bf { numerator increased by 400% = 400 / 100 = 4 } [ / tex]

[Tex ] \ text maths bf { denominator increased by 500% = 500 /100 = 5 } [ / Tex ]

[ Tex ] \ text maths bf { n = numerator and d = denominator } [ / Tex ]

[ Tex ] \ text maths bf { we know that 4n +n = 5n that is value for increased x } [ / Tex ]

[ Tex ] \ text maths bf { if we consider 5d +d = 6d } [ / text ]

[ Tex ] \ text maths bf { given resultant fraction 10/ 21 } [ / Tex ]

[ Tex ] \ text maths bf { 4n = 10 10 numerator given } [ / Tex ]

[ Tex ] \ text maths bf { 5d = 21 21 denominator given } [ /Tex ]

[ Tex ] \ text maths bf { numerator denominator } [ / Tex ]

[ Tex ] \ text maths bf { 10 / 4 } / { 21 / 5 } [ / Tex ]

[ Tex ] \ text maths bf { 10 / 4 5/ 21 = 50 / 84.} [ / Tex ]

[ text ] \ text maths bf { hence your answer is 50/ 84 } [ / Tex ]

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hope it helps

thank you