Math, asked by arjun1628, 1 year ago

if the numerator of certain is increased 200%and the demonator 150% increased the new fraction thus formed 9/10 what is the original fraction

Answers

Answered by inhumandrowsey
1

Let the original fraction be x/y

now x + 200% of x = x + 200x/100 = 300x/100

y = y + 150% of y = y + 150y/100 = 250y/100

Now x/y = (300x/100) / (250y/100) = 300x/250y

300x/250y = 9/10

x/y = 2250/3000

x/y = 15/20 = 3/4

Our original fraction was 3/4

Answered by Kanagasabapathy
0
Let's consider, x=numerator,y=denominator


numerator of certain is increased 200% means, (x+ 200x/100)=3x

denominator increased 150% means,
(y+150y/100)=y + 3y/2 =2y+3y /2 =5y/2

so from the question,(3x) / (5y/2)=9/10

==∆ 6x / 5y =9/10

==∆ x/y =9/10 × 5/6

==∆ x/y =45/60

==∆ x/y = 3/4
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