if the numerator of certain is increased 200%and the demonator 150% increased the new fraction thus formed 9/10 what is the original fraction
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Let the original fraction be x/y
now x + 200% of x = x + 200x/100 = 300x/100
y = y + 150% of y = y + 150y/100 = 250y/100
Now x/y = (300x/100) / (250y/100) = 300x/250y
300x/250y = 9/10
x/y = 2250/3000
x/y = 15/20 = 3/4
Our original fraction was 3/4
Answered by
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Let's consider, x=numerator,y=denominator
numerator of certain is increased 200% means, (x+ 200x/100)=3x
denominator increased 150% means,
(y+150y/100)=y + 3y/2 =2y+3y /2 =5y/2
so from the question,(3x) / (5y/2)=9/10
==∆ 6x / 5y =9/10
==∆ x/y =9/10 × 5/6
==∆ x/y =45/60
==∆ x/y = 3/4
numerator of certain is increased 200% means, (x+ 200x/100)=3x
denominator increased 150% means,
(y+150y/100)=y + 3y/2 =2y+3y /2 =5y/2
so from the question,(3x) / (5y/2)=9/10
==∆ 6x / 5y =9/10
==∆ x/y =9/10 × 5/6
==∆ x/y =45/60
==∆ x/y = 3/4
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