Question

If the numerator of the fraction is increased by 15 % and denominator is increased by 10% value of the fraction is 15/26 tha orignal fraction is

Answer 1

Let the original fraction be x/y .

$\LARGE\underline{\underline{\sf \red{G}\blue{i}\green{v}\orange{e}\red{n}:}}$

Numerator is inc by 15%

denominator is inc by 10% .

new fraction = 15/26.

$\LARGE\underline{\underline{\sf \red{T}\blue{o}\:\green{F}\orange{i}\pink{n}\red{d}:}}$ Original fraction

$\LARGE\underline{\underline{\sf \red{S}\blue{o}\green{l}\orange{u}\pink{t}\green{i}\</strong><strong>c</strong><strong>y</strong><strong>a</strong><strong>n</strong><strong>{o}\red{n}:}}$

A/q,

(x+0.15x)/(y+0.1y) = 15/26

1.15x/1.1y = 15/26

115x/110y = 15/26

x/y = (110*15)/(115*26)

x/y = 55*3/23*13

x/y = 165/299 (Ans)

so, the original fraction was (165/299).

(Hope it helps you)