Question

If the object inside the box was made of a material with a refractive index less than 1.5 then the A. lateral shift of the rays would have been less. B. lateral shift of the rays would have been more. C. lateral shift of the rays would remain the same as before. D. there is not enough information to comment on any of the above statements​

Answer 1

If the object inside the box was made of a material with a refractive index less than 1.5 then the A. lateral shift of the rays would have been less.

Lateral shift- The perpendicular distance between the incident ray and the emergent ray is called lateral shift.

$Lateral\ Shift = \frac{t}{cos\ r}\ sin(i-r)$

If the object inside the box was made of a material with refractive index less than 1.5 and all other factors are kept constant, then

• Angle of refraction will be increased, as the refracted ray will move away from normal.
• Thus, (i-r) value will decrease. Sine value decreases as the value of angle decreases.
• Cosine value increases with decrease in value.
• Hence, the numerator value in the given formula will decrease while denominator value will increase.
• Thus, lateral shift will reduce.

Answer 2

Answer:

Option (c)

Explanation:

Lateral shift of the rays would have been less.