If the object is released from 80 m then calculate its velocity at ground. Also calculate time required to reach the object at ground.
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Answered by
4
Answer: 4 seconds.
Explanation:
1. Given : Height from where the object is released = s = 80 metres. Gravitational force = a = 10 m/s² Initial velocity = u = 0 m/s.
2. To find: Time taken by the object to reach the ground.
3. Using the second equation of motion : S=ut+½×at² 80=0×t+½×10×t² 80=5t² 16=t² t = 4 seconds.
Explanation:
1. Given : Height from where the object is released = s = 80 metres. Gravitational force = a = 10 m/s² Initial velocity = u = 0 m/s.
2. To find: Time taken by the object to reach the ground.
3. Using the second equation of motion : S=ut+½×at² 80=0×t+½×10×t² 80=5t² 16=t² t = 4 seconds.
Answered by
2
Answer:
Answer: 4 seconds.
Explanation:
1. Given : Height from where the object is released = s = 80 metres. Gravitational force = a = 10 m/s² Initial velocity = u = 0 m/s.
2. To find: Time taken by the object to reach the ground.
3. Using the second equation of motion : S=ut+½×at² 80=0×t+½×10×t² 80=5t² 16=t² t = 4 seconds.
Explanation:
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