If the one place number of a 2- digit number is "x". The ten place number is 3 times of x . Then write the number
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Answer:
The possible numbers are 31, 62, 93.
Step-by-step explanation:
Let's say the number is 10y + x,
So,
Ones digit is x and tens place as y.
But given,
y = 3x
So,
The number is 10(3x) + x
= 30x + x
Now,
Is the important part, we know that, 30x + x is a 2 digit number.
Let's take x = 0
Number = 30(0) + 0 = 0
Let's take x = 1
Number = 30(1) + 1 = 31
Let's take x = 2
Number = 30(2) + 2 = 62
Let's take x = 3
Number = 30(3) + 3 = 93
Let's take x = 4
Number = 30(4) + 4 = 124
Hence,
We see that,
0 < x < 4, when x is a natural number, only then will we get a 2 digit number.
Which means x = 1, 2, 3
So,
The possible numbers are 31, 62, 93.
Hope it helped and believing you understood it........All the best
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