If the opposite angle of a parallelogram are (60-3x) and (x-20) find all the angles of the parallelogram
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We know that opposite angles of a parallelogram are equal. Therefore,
given 2 angles are of equal magnitude.
3x−2=50−x
3x+x=50+2
x=13
Therefore the angle are;
50−x=>50−13=370
3x−2=>3(13)−2=39−2=370
The other 2 angles of parallelogram are
180−37=1430
Therefore all angles of parallelogram are;
370,1430,370,1430
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