Math, asked by Nitishmishra, 1 year ago

if the opposite angle of a parallelogramar(3x-5)degree and(51-x) degree find the measure of each angle

Answers

Answered by Anant02
3
we know
opposite angles of parallelogram are equal
so
3x-5 = 51-x
4x = 51 + 5
x = 56 ÷ 4
x = 14
3x - 5 = 3×14-5 =42 - 5 = 37
51 -x =51 -14=37
other angle = 180 - 37 = 143
angles are 37, 143, 37 ,143
Answered by Preetigupta1
1
Given,
Opposite angles are (3x-5)° and (51-x)
as we know that in parallelogram opposite angles are always equal.

2{(3x-5)°+(51-x)}
= 2{3x-5°+51°-x}
= 2{3x-x-5°+51°}
= 2× {2x + 46°}
= 4x+ 92°
= x=92°/4
= x= 23°

hence,
(3x-5)°. and (51-x)
= (3×23)°. = (51-23)°
= 69°. = 28° // answeer
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