if the opposite angles of a parallelogram are (3x-3) degree and (6x-69) degree, find all angles of parallelogram
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Answer:
Let the parallelogram be ABCD
Then the angles will be A,B,C and D
angle A = 3x-3
and angle C = 6x-69
The opposite angles of a parallelogram are equal
3x-3 = 6x-69
69-3 = 6x-3x
3x = 66
x = 22
the angles are:
angle A =
3x-3 = 3*22-3
= 66-3
= 63 degree
Angle C=
6x-69= 6*22 -69
= 132-69
=63 degree
the sum of adjacent angles in a llgm. is 180 degree
angle A + angle B=180
63+ angle B=180
angle B = 117 degree
angle B= angle D = 117 degree
Hope it helps you...
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