Question

If the ordered pairs (3a+4b,5a-3b)and (29,0) then find a and b.
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Answer 1

Answer:

Actually didn't understand the question but no worries I'm here to help you!

Step-by-step explanation:

28+1 ಠᴥಠ

Answer 2

Given,

Ordered pairs are (3a + 4b,5a - 3b) and (29,0)

find values of a and b .

SOLUTION :-

from the question,

$3a + 4b = 29 \: \: \: \: - - - (1)$

$5a - 3b = 0$

$= > \: 5a = 3b$

$= > \: \: a = \frac{3b}{5} \: \: \: - - - (2)$

substituting eq(2) in eq(1), we get

$\rm⇢ \: \: (3 \times \frac{3b}{5}) + 4b = 29$

$\rm⇢ \: \: 29b = 29 \times 5$

$\rm⇢ \: \: b = 5$

then, from eq(2),

$\rm⇢ \: \: a = \frac{3 \times 5}{5}$

$\rm⇢ \: \: a = 3$

Final Answer :-

value of a is 3 and,

value of b is 5 .