Question

If the origin is shifted to the point (2,-1), find the new equation of the locus 2 x^2 + 3 xy - 9 y^2 - 5 x - 24 y - 7 = 0, axes remaining parallel.​

Answer 1

Answer:

Origin is shiftef to (2,−1)

=>For transformed equation replace x by x−2 and y by y+1

Now equation

2(x−2)^2+3(x−2)(y+1)−9(y+1)^2−5(x−2)−24(y+1)−7=0

2x2−10x+3xy−48y−9y^2−28=0